Question

The energy released per one fission of $U$${}^{238}$ is $200MeV$. The number of fissions per second which can produce a power of $1KW$ is

• A. 6.25 x 10${}^{13}$
• B. 3.125 x 10${}^{13}$
• C. 6.25 x 10${}^{15}$
• D. 3.125 x 10${}^{15}$

Answer 1

The correct option is B 3.125 x 10${}^{13}$

Energy released in 1 nuclear fission $=200MeV$

Power of the reactor $=1\times {10}^{3}watts$
No of fission taking place per second $=\frac{{10}^3}{200\times {10}^3\times 1.6\times {10}^{-16}}fissions/sec$

$=3.125\times {10}^{13}fissions/sec$