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Question

The energy required to charge a parallel plate condenser (capacitor) of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is :

A
12ε0E2/Ad
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B
ε0E2/Ad
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C
ε0E2Ad
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D
12ε0E2Ad
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Solution

The correct option is D ε0E2Ad
Energy given by the cell
E=CV2

Here, C= capacitance of condenser
=Aε0d

V= potential difference across the plates =Ed

Therefore, E=(Aε0d)(Ed)2=Aε0E2d

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