Question

# The enthalpy of combustion of carbon and carbon monoxide are $$-393.5$$ and $$-283\ kJ/mol$$ respectively. The enthalpy of formation of carbon monoxide per mole is:

A
110.5 kJ
B
676.5 kJ
C
676.5 kJ
D
110.5 kJ

Solution

## The correct option is D $$-110.5\ kJ$$I: $$C(s)+O_2(g)\rightarrow CO_2; \Delta H_1=-393.5\ kJ/mol$$II: $$CO(g)+\displaystyle\frac{1}{2}O_2(g)\rightarrow CO_2(g); \Delta H_2=-283.0\ kJ/mol$$On substracting II from I we get the formation reaction of carbon monoxide.III: $$C(s)+\displaystyle\frac{1}{2}O_2(g)\rightarrow CO(g); \Delta H=\Delta H_1-\Delta H_2=-110.5\ kJ/mol$$This equation III represents the formation of $$1$$ mole of $$CO$$ and thus enthalpy of formation of $$CO$$(g) is $$-110.5\ kJ/mol$$.Chemistry

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