Question

The enthalpy of Neutralisation of HCl and NaOH is $x$ $kJ$. The heat evolved when $500$ ml of $2$ N HCl is mixed with $250$ ml of $4$ N $NaOH$ will be:

• A. $x$
• B. $\frac{x}{2}$
• C. $\frac{x}{4}$
• D. $\frac{2x}{3}$

Answer 1

The correct option is A $x$

No. of gram equivalents HCl $=\frac{500\times 2}{1000}=1$

No. of gram equivalents of NaOH $=\frac{250\times 4}{1000}=1$

Enthalpy change of a reaction when 1 gram equivalents of acid is neutralised by one gram equivalents of acid is neutralized by one gram equivalents of base is called heat of neutralisation.