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Question

The enthalpy of solution of BaCl2(s) and BaCl2.2H2O(s) are – 20.6 and 8.8 kJ mol1 respectively, the enthalpy change for the hydration of BaCl2(s) is:


Your Answer
A
29.4 kJ
Your Answer
B
– 11.8 kJ
Correct Answer
C
– 29.4 kJ
Your Answer
D
+ 11.8 kJ

Solution

The correct option is B – 29.4 kJ
(i)BaCl2(s)BaCl2(aq);ΔH1=20.6kJ(ii)BaCl22H2O(s)BaCl2(aq);ΔH2=8.8kJSubtracting (ii) from (i) we getBaCl2(s)BaCl2.2H2O(s);ΔH1ΔH2=29.4kJ

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