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Question

The entropy change when two moles of ideal monoatomic gas is heated from 200oC to 300oC reversibly and isochorically is:


Your Answer
A
32R ln (300200)
Your Answer
B
52R ln (573273)
Correct Answer
C
3R ln (573473)
Your Answer
D
32R ln (573473)

 

Solution

The correct option is C 3R ln (573473)
We know that for a reversible process and an ideal system S=nCv ln T2T1+nR ln V2V1
For an isochoric process, volume is constant i.e. V1=V2
so, S=nCv ln T2T1
Given, number of moles, n=2
since gas is monoatomic Cv=3R2 T1=473K, T2=573K
putting above values we get,
S=2×32R ln (573473)
S=3R ln (573473)

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