Question

The equation for a wave travelling in x - direction on a string is
$y=\left(3.0cm\right)sin\left[\right(3.14c{m}^{-1})x-(314s^{-1}\left)t\right]$. The maximum velocity of a particle of the string approximately is (in m/s) :

Answer 1

For a wave of equation $y=Asin[kx-\omega t]$,

velocity of a particle is given as $v=\frac{dy}{dt}=A\omega cos[kx-\omega t]$

Thus $v_{max}=A\omega =3cm\times 314s^{-1}=9.4m/s$