The equation for the burning of octane is-2 C 8 H 18-25 O 2- 16 CO 2-18 H 2 OWhat volume- at STP- is occupied by 8 moles of carbon dioxide-A- 180-2B- 170-1C- 190-1D- 195E- 179-2F- 165

The correct option is E 179.2 ...

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Standard X

Chemistry

Mole Concept in Balanced Reaction

The equation ...

Question

The equation for the burning of octane is:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

What volume, at STP, is occupied by 8 moles of carbon dioxide ?

180.2

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165

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179.2

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170.1

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190.1

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195

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Solution

The correct option is C
179.2

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The equation for the burning of octane is:
2C₈H₁₈ + 25O₂ $\overset{}{\to}$ 16CO₂ + 18H₂O
(i) How many moles of carbon dioxide are produced when one mole of octane burns?
(ii) What volume, at STP, is occupied by the number of moles determined in (i)?
(iii) If the relative molecular mass of carbon dioxide is 44, what is the mass of carbon dioxide produced by burning two moles of octane?
(iv) What is the empirical formula of octane?

The equation for the burning of octane is:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

How many moles of carbon dioxide are produced when one mole of octane burns?

The equation for the burning of octane is:

$2 C_{8} H_{18} + 25 O_{2} \to 16 C O_{2} + 18 H_{2} O$

If the relative molecular mass of carbon dioxide is 44.What is the mass of carbon dioxide produced by burning two moles of octane?

Q. The volume occupied by 0.01 moles of helium gas at STP is:

Q. What is the volume occupied by 0.25 moles of

N H_{3}

gas at STP?

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The equation for the burning of octane is: 2C8H18 + 25O2 → 16CO2 + 18H2O What volume, at STP, is occupied by 8 moles of carbon dioxide ?

The correct option is C 179.2

The equation for the burning of octane is:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

What volume, at STP, is occupied by 8 moles of carbon dioxide ?

The correct option is C
179.2