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Question

The equation (m being real), mx2+2x+m=0 has two distinct roots if -


  1. m0

  2. m  0, 1

  3. m  1, – 1

  4. m  0, 1, –1


Solution

The correct options are
B

m  0, 1


Step 1:- For, mx2+2x+m=0, value of discriminant:
             D=(2)24m2=44m2

Step 2:- The roots of quadratic equation are real and distinct only when D>0

Step 3:- 4(1m2)>0
              (1m2)>0
              m2<1

             1<m<1
   

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