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Question

The equation of a circle with centre (2,2) and passes through the point (4,5) is 
  1. x2+y24x+4y5=0
  2. x2+y24x4y+5=0
  3. x2+y2+4x4y5=0
  4. x2+y24x4y5=0


Solution

The correct option is D x2+y24x4y5=0
Equation of circle
(x2)2+(y2)2=r2
Circle passes through the point (4,5)
(42)2+(52)2=r2r2=4+9=13

So, the equation of circle
(x2)2+(y2)2=13x2+y24x4y5=0

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