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Question

The equation of a hyperbola, conjugate to the hyperbola x2+3xy+2y2+2x+3y=0 is?

A
x2+3xy+2y2+2x+3y+1=0
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B
x2+3xy+2y2+2x+3y+2=0
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C
x2+3xy+2y2+2x+3y+3=0
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D
x2+3xy+2y2+2x+3y+4=0
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Solution

The correct option is B x2+3xy+2y2+2x+3y+2=0
H:x2+3xy+2y2+2x+3y=0
Let the pair of asympt at is be
A:x2+3xy+2y2+2x+3y+k=0
It represent a apir of straight lines, satisfying the condition :
abc+2fghaf2bg2ch2=0
1×2×k+2(32)×1×(32)1(32)22(1)2k(32)2=0
2k+94294k=0 k=1
A2.x2+3xy+2y2+2x+3y+1=0
As H+C=2A C (conjugate =2AH hypergate)
C:x2+3xy+2y2+2x+3y+2=0

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