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Question

The equation of a plane passing through (1, 2, –3), (0, 0, 0) and perpendicular to the plane 3x – 5y + 2z = 11, is :

A
3x+y+53z=0
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B
4x + y + 2z = 0
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C
3xy+z3=0
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D
x + y + z = 0
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Solution

The correct option is D x + y + z = 0
Equation of plane through (0, 0, 0) is
ax + by + cz = 0 . . . .(1)
(1) passes through (1, 2, –3) and ⊥ to the plane
3x – 5y + 2z = 11
a + 2b – 3c = 0 . . . .(2)
3a – 5b + 2c = 0 . . . .(3)
a11=b11=c11
a=b=c
Hence, equation of required plane is x + y + z = 0.

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