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Question

The equation of a straight line(s) passing through (1,2) and having intercept of length 3 units between the straight lines 3x+4y=24 and 3x+4y=12, is
  1. y=2
  2. x=1
  3. 7x+24y+41=0
  4. 7x24y+41=0


Solution

The correct options are
B x=1
D 7x24y+41=0
​​​ Let the line passing through (1,2) makes an angle of α with the given  parallel lines


Now the distance between the parallel lines is 125 units
So, from diagram tanα=43
If the slope of the required line is m, then  m= tan(θ±α) , where tanθ is slope of given line = 34
m=3/4±4/311=,724
So the equation of required lines are
x=1,7x24y+41=0

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