Question

# The equation of a straight line which cuts off an intercept of $$5$$ units on negative direction of y-axis and makes an angle $$120^{\circ}$$ with positive direction of x-axis is

A
y+3x+5=0
B
y3x+5=0
C
y+3x5=0
D
y3x5=0

Solution

## The correct option is A $$y + \sqrt {3}x + 5 = 0$$Equation of line $$y=mx+c$$$$m=Slope$$$$c=Intercept$$$$m=tan 120=-\sqrt{3}$$$$c=-5$$ (given)Putting value of $$m$$ and $$c$$we get $$y=-\sqrt{3}x-5$$or $$y+\sqrt{3}+5=0$$So correct answer will be option AMathematics

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