The equation of a wave on a string of linear mass density 0-04 kg m-1 is given by y-0-02msin -2- t0-04s-x0-50m- The tension in the string is

The correct option is B 6.25 N T=μv^2=μt_0^2k^2=0.04(2π/0.04)^2(2π/0.50)^2=6.25N #160; ...

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Relating Circular Motion to SHM

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Question

The equation of a wave on a string of linear mass density $0.04 k g m^{- 1}$ is given by $y = 0.02 (m) sin [2 π (\frac{t}{0.04 (s)} - \frac{x}{0.50 (m)})]$ . The tension in the string is

4.0 N

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12.5 N

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0.5 N

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6.25 N

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Similar questions

0.04 k g . m^{- 1}

y = 0.02 (m) sin [2 π (\frac{t}{0.04 (s)} - \frac{x}{0.50 (m)})]

y = 0.02 (m) s i n [2 π (\frac{t (s)}{0.04} - \frac{x (m)}{0.50})]

A transverse wave described by

$y = (0.02 m) s i n [(1.0 m^{- 1}) x + (30 s^{- 1}) t]$

propagates on a stretched string having a linear mass density of $1.2 \times 10^{- 4} k g m^{- 1}$ . Find the tension in the string.

5 {g m}^{- 1}

y = 0.03 sin (450 t - 9 x)

S I

y = 0.02 sin (x + 30 t)

12 g m^{- 1}

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