The equation of a wave propagating along a stretched string is given by Y-4sin 2- -t-0-02-x-100- where Y and x are in cm and t in second- Determine direction in which wave is propagating-

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Standard XII

Physics

Wave in Negative X-Direction

The equation ...

Question

The equation of a wave propagating along a stretched string is given by $Y = 4 sin 2 π [(t / 0.02) - (x / 100)]$ , where $Y$ and $x$ are in cm and $t$ in second. Determine direction in which wave is propagating.

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Solution

Comparing the given equation with general wave equation given by

$[Y = A sin (ω t - k x + ϕ)]$ or $[Y = A sin 2 π [(t / T) - (x / λ) + ϕ]$ .

On comparing the given equation with the general equation we find that:
The wave is propagating along $+$ ve x-axis.

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The equation of a wave propagating along a stretched string is given by Y=4sin2π[(t/0.02)−(x/100)], where Y and x are in cm and t in second. Determine direction in which wave is propagating.

Comparing the given equation with general wave equation given by[Y=Asin(ωt−kx+ϕ)] or [Y=Asin2π[(t/T)−(x/λ)+ϕ]. On comparing the given equation with the general equation we find that:The wave is propagating along +ve x-axis.

The equation of a wave propagating along a stretched string is given by $Y = 4 sin 2 π [(t / 0.02) - (x / 100)]$ , where $Y$ and $x$ are in cm and $t$ in second. Determine direction in which wave is propagating.

Comparing the given equation with general wave equation given by

$[Y = A sin (ω t - k x + ϕ)]$ or $[Y = A sin 2 π [(t / T) - (x / λ) + ϕ]$ .

On comparing the given equation with the general equation we find that:
The wave is propagating along $+$ ve x-axis.