The equation of an incident wave travelling along +X direction is given by $y = A s i n (2 t - 5 x)$ . This wave gets reflected at a rigid boundary. The equation of the reflected wave is

y = A s i n (2 t - 5 x)

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y = A s i n (2 t - 5 x + π)

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y = A s i n (2 t + 5 x + π)

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y = A s i n (2 t - 5 x + π / 2)

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Solution

The correct option is C $y = A s i n (2 t + 5 x + π)$
A reflected wave will be $π$ radians out of phase with the incident wave. Apart from this, the wave will also get reflected along the negative x axis. Thus, the sign of x also changes.
The equation of the reflected wave is thus $y = A s i n (2 t + 5 x + π)$
The correct option is (c)

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