Question

# The equation of an incident wave travelling along +X direction is given by $$y= A sin (2t-5x)$$. This wave gets reflected at a rigid boundary. The equation of the reflected wave is

A
y=Asin(2t5x)
B
y=Asin(2t5x+π)
C
y=Asin(2t+5x+π)
D
y=Asin(2t5x+π/2)

Solution

## The correct option is C $$y= A sin (2t+5x +\pi)$$A reflected wave will be $$\pi$$ radians out of phase with the incident wave. Apart from this, the wave will also get reflected along the negative x axis. Thus, the sign of x also changes. The equation of the reflected wave is thus $$y= A sin (2t+5x +\pi)$$The correct option is (c)Physics

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