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Question

The equation of circle of radius 5 units touches the coordinates axes in the second quadrant is:


A

x2 + y2 + 10x + 10y + 25 = 0

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B

x2 + y2 + 10x – 10y + 25 = 0

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C

x2 + y2 – 10x – 10y + 25 = 0

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D

x2 + y2 – 10x – 10y – 25 = 0

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Solution

The correct option is B

x2 + y2 + 10x – 10y + 25 = 0


The coordinates of the centre of the required circle is (–5, 5) and radius is 5 units. The equation of circle is:

(x + 5)2 + (y – 5)2 = (5)2

⇒ x2 + 25 + 10x + y2 + 25 – 10y = 25

⇒ x2 + y2 + 10x – 10y + 25 = 0


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