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Question

The equation of circle passing through (4, 5) and having the centre at (2, 2), is
  1. x2+y2+4x+4y5=0
  2. x2+y24x4y5=0
  3. x2+y24x=13
  4. x2+y24x4y+5=0


Solution

The correct option is B x2+y24x4y5=0
Centre (2, 2) and
R = (42)2+(52)2=13
Hence required equation is x2+y24x4y5=0.

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