The equation of line whose slope is 13 and x- intercept is 4 will be

Given: Slope = 13 and nbsp; x intercept is 4 If the nbsp;x intercept of line is 4, then line passes through (4,0) Equation of line is y 0=13(x 4) ⇒ y=1 ...

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Standard XII

Mathematics

Point Slope Form of a Line

The equation ...

Question

The equation of line whose slope is $\frac{1}{3}$ and $x -$ intercept is $4$ will be

x - 3 y + 12 = 0

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x - 6 y - 2 = 0

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4 x - y - 16 = 0

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x - 3 y - 4 = 0

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Solution

The correct option is D $x - 3 y - 4 = 0$
If the $x -$ intercept of line is $4$ , then line passes through $(4, 0)$
Equation of line is
$y - 0 = \frac{1}{3} (x - 4)$
$\Rightarrow y = \frac{1}{3} x - \frac{4}{3}$
$\Rightarrow x - 3 y - 4 = 0$

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The equation of line whose slope is 13 and x− intercept is 4 will be

The correct option is D x−3y−4=0If the x− intercept of line is 4, then line passes through (4,0) Equation of line is y−0=13(x−4) ⇒y=13x−43 ⇒x−3y−4=0

The equation of line whose slope is $\frac{1}{3}$ and $x -$ intercept is $4$ will be

The correct option is D $x - 3 y - 4 = 0$
If the $x -$ intercept of line is $4$ , then line passes through $(4, 0)$
Equation of line is
$y - 0 = \frac{1}{3} (x - 4)$
$\Rightarrow y = \frac{1}{3} x - \frac{4}{3}$
$\Rightarrow x - 3 y - 4 = 0$