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The equation of motion of a projectile are given by x = 36 t metre and 2y = 96 t – 9.8 t2 metre.  The angle of projection is                           


Solution

The correct option is B

x = 36t vx = dxdt = 36 m/s
y = 48t - 4.9t2 vy = 48 - 9.8t
at t = 0 vx = 36 and vy = 48 m/s
So, angle of projection θ = tan1(vyvx)  = tan1(43
Or θ = sin1(45)

Method II:
Comparing with the standard equations for positions x and y  of a projectile we get,
vx = 36 and vy = 48 m/s
So, angle of projection θ = tan1(vyvx)  = tan1(43
Or θ = sin1(45)

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