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The equation of the bisector of the lines 4x+3y-6=0 and 5x+12y+9=0 containing the origin is given by  .
  1. 7x-9y-3=0
  2. 7x+9y+3=0
  3. 7x+9y-3=0
  4. 7x-9y+3=0


Solution

The correct option is C 7x+9y-3=0
We firstly write the equations of lines in such form where signs of constant terms is same (let's say positive).
-4x-3y+6=0 and 5x+12y+9=0
Now, the equation of the bisector containing the origin will be the one corresponding to the positive sign.
4x3y+6(4)2+(3)=+5x+12y+952+1224x3y+65=5x+12y+91352x39y+78=25x+60y+457x+9y3=0

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