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Question

The equation of the circle passing through $$(2,0)$$ and $$(0,4)$$ and having the minimum radius is


A
x2+y2=20
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B
x2+y22x4y=0
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C
x2+y2=4
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D
x2+y2=16
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Solution

The correct option is A $$x^{2}+y^{2}-2x-4y=0$$
Given points are $$(2,0)$$ and $$(0,4)$$

Therefore, equation of circle is $$(x-2)(x-0)+(y-0)(y-4)=0$$

By expanding, we get

$$x^{2}-2x+y^{2}-4y=0$$

Option B is correct.

Mathematics

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