The equation of the hyperbola, referred to its axes as axes of coordinates, given that the distance of one of its vertices from the foci are 9 & 1 units is
A
x216−y29=1
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B
x29−y216=1
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C
x216−y29=−1
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D
−x29−y216=−1
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Solution
The correct option is Ax216−y29=1 Given, (ae−a)=1 (a+ae)=9 e−1e+1=19 (e+1+e−1)(e+1)−(e−1)=(9+1)(9−1) e=108 e=5/4 ∴a=4 ∴x216−y29=1