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Question

The equation of the internal bisector of angle BAC of the triangle ABC whose vertices are A(5,2), B(2,3), C(6,5) is

A
6x+y32=0
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B
x4y+3=0
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C
2x+y12=0
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D
y2=0
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Solution

The correct option is C 2x+y12=0
A(5,2)B(2,3)C(6,5)
vertices of D=(2+62,5+32)=(4,4)
Let A(5,2)D(4,4)
Two point slope form,
(x1,y1)(x2,y2)(5,2)(4,4)(y2)=4245(x5)y2=2(x5)2x10=y+22x+y12=0
883785_300078_ans_d08a7335dbc6496fbe9eabc90d1cf51e.jpg

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