CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the line cutting off an intercept of 3 on the Y-axis and parallel to the line joining points A(4, -5) and B(1, 2) is .

A
3x+7y-9 = 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3x-7y+9 = 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3y-7x+9 = 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3y+7x-9 = 0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 3y+7x-9 = 0
SlopeAB= 2−(−5)1−4=−73Since parallel lines have same slope,Slope of the required line=−73Given Y−intercept=3∴ Equation of the required line isy=−73x+3⇒3y=−7x+9⇒3y+7x−9=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Straight Line
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon