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Question

The equation of the line perpendicular to the line 2x+3y+5=0 and passing through (1,1), is


A
3x2y+1=0
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B
3x2y=2
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C
3x2y=1
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D
3x2y+2=0
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Solution

The correct option is C 3x2y=1
Equation of line perpendicular to the given line is
3x2y+λ=0     ...(i)
Since, it passes through point (1,1).
  32+λ=0λ=1
On putting the value of λ in Eq. (i), we get
3x2y1=0

Mathematics

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