The equation of the line whose slope is 3 and which cuts off an intercept 3 from the positive x - axis is

y=3x-9

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y=3x+3

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y=3x+9

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None of these

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Solution

The correct option is A y=3x-9
Obviously $m = t a n θ = \frac{- c}{3} \Rightarrow 3 = \frac{- c}{3} \Rightarrow c = - 9$

Hence the required equation is y=3x-9

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Q. The equation of the line whose slope is 3 and which cuts off an intercept 3 from the positive x - axis is

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The equation of the line whose slope is 3 and which cuts off an intercept 3 from the positive x - axis is

The correct option is A y=3x-9Obviously m=tanθ=−c3⇒3=−c3⇒c=−9 Hence the required equation is y=3x-9

The correct option is A y=3x-9
Obviously $m = t a n θ = \frac{- c}{3} \Rightarrow 3 = \frac{- c}{3} \Rightarrow c = - 9$

Hence the required equation is y=3x-9