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Question

The equation of the perpendicular bisector of the line segment joining the points (1, 4) and (3, 6) is


A

x – y – 7 = 0

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B

x + y – 7 = 0

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C

x + y + 7 = 0

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D

None of these

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Solution

The correct option is B

x + y – 7 = 0


Let A ≡ (1, 4) and B ≡ (3, 6). Let CD be the perpendicular bisector of the line segment AB.

Now, Slope of AB=6431=1,

Slope of CD = –1 ( CD AB)

Since C is the mid point of AB,

COOrdinates of C are (1+32,4+62) or (2,5)

Equation of CD is

(y – 5) = –1(x – 2) or x + y – 7 = 0


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