The equation of the perpendicular bisector of the line segment joining the points (1, 4) and (3, 6) is
x + y – 7 = 0
Let A ≡ (1, 4) and B ≡ (3, 6). Let CD be the perpendicular bisector of the line segment AB.
Now, Slope of AB=6−43−1=1,
∴ Slope of CD = –1 (∵ CD ⊥ AB)
Since C is the mid point of AB,
∴ COOrdinates of C are (1+32,4+62) or (2,5)
∴ Equation of CD is
(y – 5) = –1(x – 2) or x + y – 7 = 0