Question

# The equation of the plane through the point $$(2, 5, -3)$$ perpendicular to the planes $$x+2y+2x=1$$ and $$x-2y+2x=4$$ is

A
3x4y+2z20=0
B
2xz7=0
C
x2y+z=11
D
10xy4z=27

Solution

## The correct option is C $$2x-z-7=0$$$${ P }_{ 1 }:x+2y+2z=1\\ { P }_{ 2 }:x-2y+2z=4$$Let $${ l }_{ 1 }{ m }_{ 1 }{ n }_{ 1 }$$ be directions of the plane perpendicular.$$\therefore l+2m+2n=0\\ l-2m+2n=0\\ \cfrac { l }{ 8 } =\cfrac { m }{ 0 } =\cfrac { n }{ -4 } \\ (l,m,n)=(2,0,-1)\\ 2(x-2)+0(y-5)+(-1)(z+3)=0\\ 2x-4-z-3=0\\ 2x-z-7=0$$Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More