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Question

The equation of the plane which contains the line x4=y2=z1 and is perpendicular to the plane containing the lines x41=y54=z92 and x+84=y+62=z21

A
5x8y4z=0
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B
5x+8y4z=0
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C
5x8y+4z=0
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D
5x+8y+4z=0
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Solution

The correct option is A 5x8y4z=0
Normal vector of the plane containing the lines
=∣ ∣ ∣^i^j^k142421∣ ∣ ∣=7^j14^k
So the equation of the plane
∣ ∣xyz4210714∣ ∣=05x8y4z=0

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