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Question

The equation of the straight line meeting the circle with centre at origin and radius equal to 5 units in two points at equal distances of 3 units from point A(3, 4) is

A
6x+8y=41
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B
6x8y+41=0
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C
8x+6y+41=0
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D
8x6y+41=0
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Solution

The correct option is A 6x+8y=41
Slope of perpendicular bisector =43
Slope of the line =34
AO,AB and AC are passing through the same point
(x3)2+(y4)2=9and,x2+y2=25x2+y26x8y+25=9256x8y+25=96x+8y=41

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