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Question

# The equation of the straight line which passes through the point (3, 4) and whose intercept on y-axis is twice that on x-axis, is

A

2x – y = 10

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B

x + 2y = 10

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C

2x + y = 10

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D

None of these

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Solution

## The correct option is C 2x + y = 10 Let the equation of the line be xa+yb=1 ......(1) Given: intercept on y-axis = 2 (intercept on x-axis) i.e., b = 2a So, equation (1) becomes xa+y2a=1 or 2x + y = 2a …… (2) Since line (2) passes through the point (3, 4) ∴ 2×3+4=2a⇒a−5 Thus, the equation of the required line is 2x + y = 10

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