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Question

The equation of the tangent to the ellipse x225+y216=1 which is parallel to the line y=3x, is

A
y=3x+241
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B
y=3x+13
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C
y=3x+209
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D
none of these
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Solution

The correct option is A y=3x+241
Equation of line parallel to y=3x is given by,
y=3x+c..(1)
Now this line is tangent the ellipse, x225+y216=1
c2=a2m2+b2=9×25+16=241
c=±241
Thus required equation is, y=3x±241

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