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Question

The equation of the tangent to the parabola y2=16x inclined at an angle of 60 to the positive xaxis is

A
3x3y+4=0
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B
3x+3y+4=0
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C
3xy+4=0
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D
3x+y+4=0
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Solution

The correct option is A 3x3y+4=0
Given parabola y2=16x
Inclination of the tangent is
θ=60m=tan60=3
Therefore equation of the tangent is of the form, y=mx+am
y=3x+43
3y=3x+4

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