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Question

The equation tan4x2sec2x+a=0 will have at least one solution if : 
  1. a3 
  2. a2
  3. a3
  4. a3


Solution

The correct option is C a3
tan4x2sec2x+a=0tan4x2(1+tan2x)+a=0tan4x2tan2x+1=3a(tan2x1)2=3a
Since, (tan2x1)20
So, equation to have solution
3a0a3

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