The equation to the pair of tangents drawn from (–1, –2) to parabola $x^{2} = 2 y$ is

x^{2} - 2 x y - 3 y^{2} + 10 x + 6 y + 9 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 x^{2} - 2 x y - y^{2} + 4 x - 6 y - 4 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + 2 x y + 3 y^{2} + 10 x + 6 y + 9 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 x^{2} + 2 x y - 3 y^{2} + 4 x - 6 y - 4 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $4 x^{2} - 2 x y - y^{2} + 4 x - 6 y - 4 = 0$
Equation of pair of tangents is given by $T^{2} = S S_{1}$
Equation of pair of tangents from $(- 1, - 2) i s [- x - (y - 2)^{2}] = (x^{2} - 2 y) (1 + 4)$
$\Rightarrow (- x - y + 2)^{2} = 5 (x^{2} - 2 y) \Rightarrow 4 x^{2} - y^{2} - 2 x y + 4 x - 6 y - 4 = 0$

Suggest Corrections

Similar questions

(1, 4)

y^{2} = 12 x

(2, - 1)

x^{2} + 3 y^{2} = 3

(2, 1)

x^{2} = 2 y

x^{2} = 2 y

y^{2} = 4 x

Join BYJU'S Learning Program