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Question

The equation whose roots are 2,1±3i is

A
x34x2+14x20=0
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B
x3x2+5x14=0
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C
x3+2x23x10=0
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D
x33x214x+10=0
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Solution

The correct option is A x34x2+14x20=0
Roots are 2,1+3i,13i
Then Sum of roots S1=2+1+3i+13i=4
S2=2×(1+3i)+2×(13i)+(1+3i)(13i)
=2+6i+26i+13i+3i+9=14
S3=2×(1+3i)×(13i)=2(1+9)=20
Hence using x3S1x2+S2xS3=0 equation is x34x2+14x20=0.

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