Question

# The equation $${ x }^{ 2 }+{ y }^{ 2 }=9$$ meets x-axis at

A
(±3,0)
B
(±9,0)
C
(±1,0)
D
(-5/14, 5/14)

Solution

## The correct option is C $$(\pm 3,0)$$$$x^2+y^2=9$$ The equation meets x-axis if the y-coordinate is $$0$$So $$x^2+0=9\\x^2=9\\x=\sqrt9\\x=\pm 3$$So the point is $$(\pm 3,0)$$Mathematics

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