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Question

The equation $${ x }^{ 2 }+{ y }^{ 2 }=9$$ meets x-axis at 


A
(±3,0)
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B
(±9,0)
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C
(±1,0)
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D
(-5/14, 5/14)
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Solution

The correct option is C $$(\pm 3,0)$$
$$x^2+y^2=9$$ 
The equation meets x-axis if the y-coordinate is $$0$$
So $$x^2+0=9\\x^2=9\\x=\sqrt9\\x=\pm 3$$
So the point is $$(\pm 3,0)$$

Mathematics

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