CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The equation xlogx=3x


A
has no root in (1,3)
loader
B
has exactly one root in (1,3)
loader
C
xlogx(3x)>0 in [1,3]
loader
D
xlogx(3x)<0 in [1,3]
loader

Solution

The correct option is B has exactly one root in (1,3)
f(x)=xlogx3+x
f(x)=1+logx+1=2+logx
So f(x) is monotonically increasing

We now that,
f(1)f(3)=2(3log3)<0
By using intermmediate value theorem,
Hence, one root must lie in (1,3).

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image