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Question

The equations of the bisectors of the lines 3x-4y+7=0 and 12x-5y-8=0 are:

A
21x+27y-131=0
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B
21x-27y+131=0
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C
99x-77y+51=0
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D
99x+77y-51=0
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Solution

The correct options are
A 21x+27y-131=0
C 99x-77y+51=0
The equations of the bisectors are :
3x4y+732 + (4)2=±12x5y8122+(5)23x4y+75=±12x5y81339x52y+91=±(60x25y40)21x+27y131=0 or 99x77y+51=0

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