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Question

The equations of the line passing through the point(1,2,-4) and perpendicularto the two lines x83=y+1916=z107 and x153=y298=z55, will be





  1. None of these


Solution

The correct option is A



Line passing through the point (1,2,-4) is x1l=y2m=z+4n
Now, according to question, 3l-16m+7n=0 and 3l+8m-5n=0
Hence required line is, x12=y23=z+46

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