    Question

# The equations of the tangents to the circle x2+y2 - 4x - 6y - 12 = 0 and parallel to 4x - 3y = 1 are

A
4x + 3y + 14 = 0, 4x + 3y + 16 = 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4x – 3y – 24 = 0, 4x – 3y + 26 = 0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x – y – 14 = 0, x – y + 16 = 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4x – 3y + 34 = 0, 4x – 3y + 16 = 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 4x – 3y – 24 = 0, 4x – 3y + 26 = 0For the circle x2+y2 - 4x - 6y - 12 = 0, centre is (2, 3), radius = 5 Equation of a line parallel to 4x - 3y = 1 is 4x - 3y + k = 0 4x - 3y + k = 0 is a tangent to the circle |4(2)−3(3)+k|5 = 5 ⇒ |k−1| = 25 ⇒ k = 1 ± 25 ⇒ k = 26 or - 24. ∴ Required tangents are 4x - 3y + 26 = 0, 4x - 3y - 24 = 0  Suggest Corrections  1      Similar questions  Related Videos   Tangent to a Circle
MATHEMATICS
Watch in App  Explore more