Question

# The equilibrium concentration of $$B\left[ { \left( B \right) }_{ e } \right]$$ for the reversible reaction $$A\rightleftharpoons B$$ can be evaluated by the expression:

A
Kc[A]1e
B
KfKb[A]1e
C
KfKb1[A]e
D
KfKb[A]1

Solution

## The correct option is C $${ K }_{ f }{ { K }_{ b } }^{ -1 }{ \left[ A \right] }_{ e }$$For given reaction, $$K_C= \cfrac {K_f}{K_b}=\cfrac {[B]_e}{[A]_e}$$$$\therefore [B]_e= \cfrac {K_f}{K_b}[A]_e$$$$= K_fK_b^{-1}[A]_e$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More