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Question

The equilibrium constant for the following reaction is 49 at 450oC. If 0.22 mol of I2, 0.22 mol of H2 and 0.66 mol of HI were put in a evacuated 1 litre container.
H2+I22HI
Then, the correct statement will be:


A
 Reaction will proceed in forward direction until equilibrium is established.
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B
Reaction will proceed in backward direction until equilibrium is established.
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C
Reaction is already at equilibrium.
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D
None of the above
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Solution

The correct option is A  Reaction will proceed in forward direction until equilibrium is established.
Given, nH2=0.22, nI2=0.2, nHI=0.66V=1L

[H2]=0.22,[I2]=0.22,[HI]=0.66

The concentration given in question are not necessarily the equilibrium concentrations.
Calculating reaction quotient Qc from these concentrations :

The reaction is
H2+I22HI

For this reaction, Qc=[HI]2[H2][I2]

putting the value,
Qc=(0.66)2(0.22)(0.22)
Qc=9.0  but Kc=49 (Given), which is greater than Qc

i.e. Kc>Qc

Hence, the reaction will move in forward direction.

Chemistry

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