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Question

The equilibrium constant Kp for the reaction
A(g)B(g)+C(g)
is 1 at 27C and 4 at 47.

For the reaction calculate enthalpy change for the
B(g)+C(g)A(g)
(Given:R=2cal/molK)

A
13.31 kcal/mol
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B
14.31 kcal/mol
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C
19.2 kcal/mol
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D
55.63 kcal/mol
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Solution

The correct option is A 13.31 kcal/mol
The equilibrium constant Kp for the reaction
A(g)B(g)+C(g)
Kp1=1at300k;Kp2=4at320k
log1041=ΔH2.303R[13001320]
0.6=ΔH2.303×2×20300×320
ΔH=13.31Kcal/mole.
forB(g)+C(g)A(g)
ΔH=13.31Kcal/mole.

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