CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The equilibrium constants, $$K_{p1}$$ and $$K_{p2}$$ for the reactions $$X\rightleftharpoons 2 Y\ and\ Z \rightleftharpoons P + Q$$ respectively are in the ratio of 1:9. If the degree of dissociation of X and Z be equal, then the ratio of total pressures at this equilibrium is:


A
1:1
loader
B
1:3
loader
C
1:9
loader
D
1:36
loader

Solution

The correct option is C 1:36
let the initial pressure of X and Z be $$P_{1}$$ and $$P_{2}$$ respectively

            $$X\quad\rightleftharpoons\quad 2Y$$

$$P_{1}(1-\alpha )  \quad\quad     2P_{1}\alpha $$

$$K_{1}= \dfrac{4P_{1}\alpha ^{2}}{1-\alpha}$$

             $$Z\rightleftharpoons\quad P +\quad Q$$

$$P_{2}(1-\alpha )\quad       P_{2}\alpha\quad    P_{2}\alpha$$

$$K_{2}= \dfrac{P_{2}\alpha ^{2}}{1-\alpha}$$

$$\dfrac{K_{1}}{K_{2}}= \dfrac{4P_{1}}{P_{2}}= \dfrac{1}{9}$$

$$\dfrac{P_{1}}{P_{2}}= \dfrac{1}{36}$$

ratio of total pressures $$ = \dfrac{P_{1}(1+\alpha )}{P_{2}(1+\alpha )}= \dfrac{P_{1}}{P_{2}}= \dfrac{1}{36}$$ 

So, the correct option is $$D$$

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image