Question

# The equilibrium constants, $$K_{p1}$$ and $$K_{p2}$$ for the reactions $$X\rightleftharpoons 2 Y\ and\ Z \rightleftharpoons P + Q$$ respectively are in the ratio of 1:9. If the degree of dissociation of X and Z be equal, then the ratio of total pressures at this equilibrium is:

A
1:1
B
1:3
C
1:9
D
1:36

Solution

## The correct option is C 1:36let the initial pressure of X and Z be $$P_{1}$$ and $$P_{2}$$ respectively            $$X\quad\rightleftharpoons\quad 2Y$$$$P_{1}(1-\alpha ) \quad\quad 2P_{1}\alpha$$$$K_{1}= \dfrac{4P_{1}\alpha ^{2}}{1-\alpha}$$             $$Z\rightleftharpoons\quad P +\quad Q$$$$P_{2}(1-\alpha )\quad P_{2}\alpha\quad P_{2}\alpha$$$$K_{2}= \dfrac{P_{2}\alpha ^{2}}{1-\alpha}$$$$\dfrac{K_{1}}{K_{2}}= \dfrac{4P_{1}}{P_{2}}= \dfrac{1}{9}$$$$\dfrac{P_{1}}{P_{2}}= \dfrac{1}{36}$$ratio of total pressures $$= \dfrac{P_{1}(1+\alpha )}{P_{2}(1+\alpha )}= \dfrac{P_{1}}{P_{2}}= \dfrac{1}{36}$$ So, the correct option is $$D$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More