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Question

The equivalent capacitance of three capacitors of capacitance C1,C2 and C3 connected in parallel is 12 units and the product C1C2C3=48. When the capacitors C1 and C2 are connected in parallel the equivalent capacitance is 6 units. Then the capacitance are :


A
1.5, 2.5, 8
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B
2, 3, 7
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C
4, 2, 6
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D
1, 5, 6
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Solution

The correct option is C 4, 2, 6
C1, C2 and C3 in parallel
Ceff=C1+C2+C3
12=C1+C2+C3 ------------ (1)
C1C2C3=48 ------------ (2)
C1 and C1 are connected in parallel
Ceff=C1+C2
C1+C2=6--------(3)
from(1) and (3),
C3=6
Hence equation (3) becomes
C1C2=8------(4)
also from (2)
C1=6C2
(6C2)C2=8
C226C2+8=0
solving this we get,
We get C1=4, C2=2, C3=6

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