Equivalent conductance of 1 M propanoic acid is 10 $o h m^{- 1} c m^{2} e q^{- 1}$ and that at infinite dilution 200 $o h m^{- 1} c m^{2} e q^{- 1}$ . The pH of the propanoic acid solution is:

Q. The conductivity of an aqueous solution of a weak monoprotic acid is

0.000032 o h m^{- 1} c m^{- 1}

at a concentration 0.2M. If at this concentration, the degree of dissociation is 0.02, then the value of

λ_{\infty}

(equivalent conductance at infinite dilution in

o h m^{- 1} c m^{2} / e q t)

is :

Q. The equivalent conductivity of a 0.01 N solution of a monobasic acid is 70.0 S

c m^{2} e q^{- 1}

. If the equivalent conductivity of the acid at infinite dilution is 350

S c m^{2} e q^{- 1} .

Then

Q. The equivalent conductivity of a 0.01 N solution of a monobasic acid is 70.0 S

c m^{2} e q^{- 1}

. If the equivalent conductivity of the acid at infinite dilution is 350

S c m^{2} e q^{- 1} .

Then

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The equivalent conductivity of monobasic acid at infinite dilution is 348 ohm−1 cm2 eq−1. If the resistivity of the solution containing 15 g acid (molar mass 49) in 1 litre is 18.5 ohm cm, what is the degree of dissociation of acid?

The equivalent conductivity of monobasic acid at infinite dilution is 348 $o h m^{- 1}$ $c m^{2}$ $e q^{- 1}$ . If the resistivity of the solution containing 15 g acid (molar mass 49) in 1 litre is 18.5 ohm cm, what is the degree of dissociation of acid?