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Valency and Oxidation States

The equivalen...

Question

The equivalent weight of oxygen, when it is converted to oxide is equal to:

\frac{m o l e c u l a r w e i g h t}{3}

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molecular weight

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\frac{m o l e c u l a r w e i g h t}{4}

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\frac{m o l e c u l a r w e i g h t}{2}

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Solution

The correct option is B $\frac{m o l e c u l a r w e i g h t}{4}$
$O_{2} + 4 e^{-}$ $\to$ ${2 O_{2}}^{-}$
Oxditaion state of $O$ in $O_{2}$ =0
Oxidation state of $O$ in oxide= $- 2$

Change in oxidation state of $O$ = $2$
$∴$ Change in oxidation state of $O_{2}$ = $4$
Equivalent weight= $\frac{M o l e c u l a r w e i g h t}{4}$

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